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Re: Maximum Allowable Error

From: Bobbi
Date: 09 Dec 2003
Time: 12:15:15

Comments

Walter,

Yes, I think I have the info. you need. Use this formula and solve for "E."

n = (K2 * sigma2) / E2

That's k squared times sigma squared, divided by E squared, where n is the sample size, K is the coefficient of normal distribution (for alpha 0.05, K is 1.96), sigma is the standard deviation, and E is the error.


Last changed: November 20, 2007