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Simple random sampling

From: TYC
Date: 1/22/2006
Time: 8:56:34 PM

Comments

My supplier presented the following formula for determining the sample size recently. The aim is to detect a 500 PPM problem in their daiy production of 400 units.

Method: Simple random sampling without replacement

sample size = [N*p*(1-p)]/[(N-1)*D^2 + p*(1-p)]

where N=400, p= 500 ppm, D = not too sure but I think is is something associated with 99.5% confidence interval.

The result sample size is 8!!! Which I find highly unbelieveable.

Can some help to shed some light on this?

Alternatively, can someone advise how we can determine an appropriate sample size in this case?

Thanks in advance.


Last changed: November 20, 2007