Questioner01 wrote:For a sample of 100 with accept number of 3, the LTPD at 10% probability of acceptance is 5.56% (attribute sampling plan).
I interpret this to mean that there is a 10% chance that up to 5.6% of the population may be defective.
The balance of the population, 94.4% I consider to be defective free.
The sampling plan is sufficient to characterize 94.4% of the population as defective free. It is not sufficient to characterize 5.6% of the population.
Is there any meaning or significance to the ratio, 94.4:5.6?
How does one interpret this ratio, or its inverse, if it has any meaning at all?
Is this something like an odds ratio?
Questioner01 wrote:As I said earlier, I erred typing 5.56%; it should have been 6.56% as you stated.
I should have been more careful and wrote: "I interpret this to mean that with a sample of 100 with three defectives observed, the LTPD at 10% probability of acceptance is 6.56% (attribute sampling plan)." Then the statement I made,"I interpret this to mean that there is a 10% chance that up to 5.6% of the population may be defective" is appropriate.
Regarding confidence limits, the LTPD value is the upper bound of the % defective for all sampling plans.
And 100 - LTPD is the lower confidence bound of the % conforming. Do you agree?
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